Class 11 Maths Chapter 4 Complex Numbers and Quadratic Equations NCERT Solutions | Full Guide
Class 11 Maths Chapter 4 Complex Numbers and Quadratic Equations NCERT Solutions | Full Guide
Class 11 Maths Chapter 4 – Complex Numbers and Quadratic Equations
Introduction
This chapter introduces a new type of number called complex numbers. These numbers help solve equations that do not have real solutions.
You will also learn how to solve quadratic equations in a better and more complete way using formulas and roots.
Complex Numbers
A complex number is written as:
Where
a = real part
b = imaginary part
i = √(-1)
Properties of i
-
i² = -1
-
i³ = -i
-
i⁴ = 1
Operations on Complex Numbers
Let z₁ = a + ib and z₂ = c + id
-
Addition: (a+c) + i(b+d)
-
Subtraction: (a-c) + i(b-d)
-
Multiplication: (ac - bd) + i(ad + bc)
Conjugate of Complex Number
If z = a + ib
Then conjugate is
z̄ = a - ib
Modulus of Complex Number
|z| = √(a² + b²)
Argand Plane
-
Real part plotted on x-axis
-
Imaginary part plotted on y-axis
Quadratic Equation
Standard form:
Discriminant
D = b² - 4ac
-
D > 0 → real and distinct roots
-
D = 0 → equal roots
-
D < 0 → complex roots
Solved NCERT Examples (Step by Step)
Example 1
Find i⁵
Solution:
i⁴ = 1
i⁵ = i⁴ × i = i
Example 2
Add (3 + 2i) and (1 - 4i)
Solution:
= (3+1) + (2i - 4i)
= 4 - 2i
Example 3
Multiply (2 + 3i)(1 + i)
Solution:
= 2 + 2i + 3i + 3i²
= 2 + 5i - 3
= -1 + 5i
Example 4
Find modulus of 3 + 4i
Solution:
|z| = √(3² + 4²)
= √(9 + 16) = 5
Example 5
Find conjugate of 5 - 2i
Solution:
= 5 + 2i
Example 6
Solve x² - 5x + 6 = 0
Solution:
(x-2)(x-3)=0
x = 2, 3
Example 7
Solve x² + 4 = 0
Solution:
x² = -4
x = ±2i
Example 8
Find discriminant of x² + 2x + 5
Solution:
D = 2² - 4×1×5 = 4 - 20 = -16
Example 9
Solve using formula: x² - 2x + 5 = 0
Solution:
x = [2 ± √(-16)]/2
= 1 ± 2i
Example 10
Find product of roots of x² + 7x + 10
Solution:
Product = c/a = 10
Practice Focus (From NCERT Exercises)
-
Simplifying powers of i
-
Operations on complex numbers
-
Finding modulus and conjugate
-
Solving quadratic equations
-
Using discriminant


















Comments
Post a Comment